(-3(x^2+7)-4x)+(2x^2-4(-2x-4))=

Solution for (-3(x^2+7)-4x)+(2x^2-4(-2x-4))= equation:

Simplifying
(-3(x2 + 7) + -4x) + (2x2 + -4(-2x + -4)) = 0

Reorder the terms:
(-3(7 + x2) + -4x) + (2x2 + -4(-2x + -4)) = 0
((7 * -3 + x2 * -3) + -4x) + (2x2 + -4(-2x + -4)) = 0
((-21 + -3x2) + -4x) + (2x2 + -4(-2x + -4)) = 0

Reorder the terms:
(-21 + -4x + -3x2) + (2x2 + -4(-2x + -4)) = 0

Remove parenthesis around (-21 + -4x + -3x2)
-21 + -4x + -3x2 + (2x2 + -4(-2x + -4)) = 0

Reorder the terms:
-21 + -4x + -3x2 + (2x2 + -4(-4 + -2x)) = 0
-21 + -4x + -3x2 + (2x2 + (-4 * -4 + -2x * -4)) = 0
-21 + -4x + -3x2 + (2x2 + (16 + 8x)) = 0

Reorder the terms:
-21 + -4x + -3x2 + (16 + 8x + 2x2) = 0

Remove parenthesis around (16 + 8x + 2x2)
-21 + -4x + -3x2 + 16 + 8x + 2x2 = 0

Reorder the terms:
-21 + 16 + -4x + 8x + -3x2 + 2x2 = 0

Combine like terms: -21 + 16 = -5
-5 + -4x + 8x + -3x2 + 2x2 = 0

Combine like terms: -4x + 8x = 4x
-5 + 4x + -3x2 + 2x2 = 0

Combine like terms: -3x2 + 2x2 = -1x2
-5 + 4x + -1x2 = 0

Solving
-5 + 4x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
5 + -4x + x2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -4x + -5 + x2 = 0 + -5

Reorder the terms:
5 + -5 + -4x + x2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -4x + x2 = 0 + -5
-4x + x2 = 0 + -5

Combine like terms: 0 + -5 = -5
-4x + x2 = -5

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -5 + 4

Reorder the terms:
4 + -4x + x2 = -5 + 4

Combine like terms: -5 + 4 = -1
4 + -4x + x2 = -1

Factor a perfect square on the left side:
(x + -2)(x + -2) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.